Question

Разложите на множители 6у²-3ху 16а-а³

Answer 1

3y(2у-х)
а(16-а^2)
вот

Answer 2

3y(2y-x)
a(16-a^2)=a(4-a)(4+a)

Answer 3

Factoring the Expression 6у²-3ху+16а-а³

To factor the expression 6у²-3ху+16а-а³, we can factor it by grouping the terms and then finding the common factors within each group.

First, let's group the terms: - Group 1: 6у²-3ху - Group 2: 16а-а³

Now, let's factor each group separately.

Factoring Group 1: 6у²-3ху

We can factor out the common factor from the terms in Group 1, which is 3у: ``` 3у(2у - х) ``` So, the factored form of Group 1 is 3у(2у - х).

Factoring Group 2: 16а-а³

We can factor out the common factor from the terms in Group 2, which is а: ``` а(16 - а²) ``` So, the factored form of Group 2 is а(16 - а²).

Factoring the Entire Expression

Now, we can factor the entire expression by combining the factored forms of Group 1 and Group 2: ``` 3у(2у - х) + а(16 - а²) ```

This is the factored form of the given expression 6у²-3ху+16а-а³.