Question

А) y=2x-1 -2x+3y=9 Б) 3х-7у=32 х=-5у-4 В) 4х+7у=40 -4+9у=24 Г) 2х-3у=-4 5х+у=7

Answer 1

Это решение всех систем уравнений)

Answer 2

To solve these systems of equations, we can use different methods like substitution, elimination, or matrix methods. Let's solve each of the systems step by step:

А)

$$\begin{cases} y=2x-1\\ -2x+3y=9 \end{cases}$$

We can substitute the value of $y$ from the first equation into the second equation:

$$-2x+3(2x-1)=9$$

Simplify and solve for $x$:

$$-2x+6x-3=9$$

$$4x=12$$

$$x=3$$

Then use the value of $x$ to find $y$ from the first equation:

$$y=2(3)-1=6-1=5$$

So the solution for system A is $x=3$ and $y=5$.

Б)

$$\begin{cases} 3x-7y=32\\ x=-5y-4 \end{cases}$$

Substitute the value of $x$ from the second equation into the first equation:

$$3(-5y-4)-7y=32$$

Simplify and solve for $y$:

$$-15y-12-7y=32$$

$$-22y=44$$

$$y=-2$$

Then use the value of $y$ to find $x$ from the second equation:

$$x=-5(-2)-4=10-4=6$$

So the solution for system Б is $x=6$ and $y=-2$.

For the rest of the systems, we can follow similar steps. Let me know if you need help with any of the other systems.