Question

2y^2-3y+2p=0 -y^2+2y-5p=0 x^2-2px+6=0 x^2-8px-4,6=0

Answer 1

Ответ:

1.2y^2-3y+2p=0

2p=-2y^2+3y

p=-y^2+3/2 y

2.-y^2+2y-5p=0

-5p=y^2-2y

p=-1/5 y^2+2/5 y

3.x^2-2px+6=0

D=(-2p)^2-4*1*6=4p^2-24

система :4p^2-24>0

4p^2-24=0

4p^2-24<0

система: p принадлежит промежутку(от минус бесконечности;до минус корня из 6)знак объединения(от корня из 6;плюс бесконечности)

p1=минус корень из 6

p2=корень из 6

p принадлежит (минус корень из 6;корень из 6).

4.x^2-8px-4,6=0

x^2-8px-23/5=0

D=(-8p)^2-4*1*(-23/5)=64p^2+92/5

2 действительных корня

Answer 2

It appears you have provided four quadratic equations, and it seems like you might want to solve for the variables y and p in terms of x. Let's work through these equations one by one:

1. 2y^2 - 3y + 2p = 0
2. -y^2 + 2y - 5p = 0
3. x^2 - 2px + 6 = 0
4. x^2 - 8px - 4,6 = 0

Let's start with the first two equations:

1. 2y^2 - 3y + 2p = 0 2. -y^2 + 2y - 5p = 0

We can solve these two equations simultaneously. To do this, we'll eliminate 'p' from the equations by equating the expressions for 'p' in both equations:

From equation (1), we have p = (3y - 2y^2) / 2.

From equation (2), we have p = (2y - y^2) / 5.

Now we can set these expressions for 'p' equal to each other and solve for 'y':

(3y - 2y^2) / 2 = (2y - y^2) / 5

Now, let's solve this equation for 'y':

Multiply both sides by 10 to eliminate fractions:

5(3y - 2y^2) = 2(2y - y^2)

Expand:

15y - 10y^2 = 4y - 2y^2

Now, bring all terms to one side of the equation:

10y^2 - 15y + 4y - 2y^2 = 0

Combine like terms:

8y^2 - 11y = 0

Now, we can factor out 'y':

y(8y - 11) = 0

So, y = 0 or 8y - 11 = 0.

If y = 0, then p can be calculated using either equation.

If 8y - 11 = 0, then y = 11/8.

Now, we have the values of 'y'. We can use these values to calculate 'p' using one of the equations. Let's use equation (1):

If y = 0, then from equation (1): 2p = 0, so p = 0.

If y = 11/8, then from equation (1): 2p = 11/4 - 33/8 + 22/64, which simplifies to 2p = 11/8 - 33/8 + 11/32.

Now, solve for 'p':

2p = (11 - 33 + 11/4) / 8

2p = (-21 + 11/4) / 8

2p = (-84 + 11) / (8 * 4)

2p = (-73) / 32

p = (-73/32) / 2

p = -73/64

So, the solutions are:

• When y = 0, p = 0.
• When y = 11/8, p = -73/64.

Now, let's move on to the next two equations:

3. x^2 - 2px + 6 = 0 4. x^2 - 8px - 4,6 = 0

It appears that there is a typo in the fourth equation, as "4,6" doesn't seem like a valid number. If you can provide the correct equation, I can help you solve it.