Question

7+2х кв.=2(х+1)*(х+3)

Answer 1

Ответ:

Объяснение:7+2x²=2(x+1)(x+3)

7+2x²=2(x²+3x+x+3)

7+2x²=2x²+8x+6

2x²-2x²-8x=6-7

-8x=-1

8x=1

X=1:8

Answer 2

To solve the equation 7 + 2x^2 = 2(x + 1)(x + 3), you can follow these steps:

1. Distribute the 2 on the right side of the equation: 7 + 2x^2 = 2(x^2 + 4x + 3)

2. Distribute the 2 into the terms inside the parentheses: 7 + 2x^2 = 2x^2 + 8x + 6

3. Now, subtract 2x^2 from both sides of the equation to get all the x^2 terms on one side: 7 = 8x + 6

4. Next, subtract 6 from both sides to isolate the term with x on the right side: 7 - 6 = 8x

5. Simplify: 1 = 8x

6. Finally, divide both sides by 8 to solve for x: 1/8 = x

So, the solution to the equation is x = 1/8.