Вопрос задан 23.10.2023 в 13:42. Предмет Алгебра. Спрашивает Файзев Илья.

Помогите хоть с чем-то пожалуйста! 1. Решите систему уравнений с помощью графика ( хотя бы без

графика если можно помогите пожалуйста ). {х-2y=4 {7х-2y=8 2. Решите систему способом сложения {4х+2y=24 {7x-2y=31 3. Решите задачу.. Пусть легковых -х, когда грузовых 8+y. Составим и решим уравнение. 4.. Сколько решений имеет система? {-x+2y=8 {x+4y=10 ЗАРАНЕЕ ОГРОМНОЕ СПАСИБО. Смотреть ответ Да у меня условия просто нет.. Поэтому это как с условия уже составляется.. Но спасибо. дальше некорректность, поэтому не могу может даже всё если исправите, решу парочку заданий не полностью она Ерофейка Ерофейка 1) {х-2у=4 {7х-2у=8 Можно использовать метод сложения: {-2у+х=4 {2у-7х=-8 (домножили на -1) 0-6х=-4 х=4/6=2/3 найдём у: 2/3-2у=4 -2у=4-2/3 -2у=10/3 у= -(10/3)/2 у= -5/3 Ответ: х=2/3;у=-5/3 2){4х+2y=24 {7x-2y=31 11х=55 х=5 найдём у: 4×5+2у=24 20+2у=24 2у=4 у=2 Ответ: х=5;у=2 Новые вопросы в Алгебра Замiнiть зірочку степенем з основою а так, щоб утворилася правильна рівність: 1) all. *= a19; 2) a³. *. a = a²5 ; 4) *: a19 = a23 ; 3) a14 :*= a6; Обч … исліть значення виразу (у разі потреби скористайтеся таблицями степенів чисел 2 і 3, квадратів двоцифрових чисел, кубiв одноцифрових чисел): 1) 2²-2³; 2) 3¹5.3¹1; 3) 59-5³:510; 4) 11¹¹:11¹0-11; 16 5) (1#)" (¹#)" ¹ #: Подайте у вигляді степеня вираз: 4) (m3)4; 1) (24)3; 2) (102 5) ((a7)3)2; 3) m'm4 . 6) (aº)³. (a²)4; 6) 5) *: a7 .all = a18; 6) a:*:a=a³. 7) 715 712 7² (0,2) ¹ (0,2) (0,2)¹5.(0,2)6 7) (-a5)3 . 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Давайте рассмотрим ваши задачи по порядку:

  1. Решение системы уравнений: x2y=4{x - 2y = 4} 7x2y=8{7x - 2y = 8}

    Метод сложения: Умножим первое уравнение на 7 и вычитаем второе уравнение: 7(x2y)(7x2y)=2887(x - 2y) - (7x - 2y) = 28 - 8 7x14y7x+2y=207x - 14y - 7x + 2y = 20 12y=20-12y = 20 y=2012=53y = -\frac{20}{12} = -\frac{5}{3}

    Теперь, подставим значение yy в первое уравнение: x2(53)=4{x - 2 \cdot \left(-\frac{5}{3}\right) = 4} x+103=4x + \frac{10}{3} = 4 x=4103=23x = 4 - \frac{10}{3} = \frac{2}{3}

    Ответ: x=23x = \frac{2}{3}, y=53y = -\frac{5}{3}

  2. Решение системы методом сложения: 4x+2y=24{4x + 2y = 24} 7x2y=31{7x - 2y = 31}

    Сначала сложим оба уравнения: (4x+2y)+(7x2y)=24+31(4x + 2y) + (7x - 2y) = 24 + 31 11x=5511x = 55 x=5511=5x = \frac{55}{11} = 5

    Теперь, подставим значение xx в первое уравнение: 45+2y=24{4 \cdot 5 + 2y = 24} 20+2y=2420 + 2y = 24 2y=24202y = 24 - 20 2y=42y = 4 y=42=2y = \frac{4}{2} = 2

    Ответ: x=5x = 5, y=2y = 2

  3. Задача о легковых и грузовых автомобилях:

    Пусть xx - количество легковых автомобилей, yy - количество грузовых автомобилей. Согласно условию, у нас есть следующая система уравнений:

    x+8+y=0-x + 8 + y = 0 (у нас 8 грузовых автомобилей больше, чем легковых) x+4y=10x + 4y = 10

    Теперь решим эту систему методом сложения. Сначала приведем первое уравнение к виду xx:

    x+8+y=0-x + 8 + y = 0 x=8yx = 8 - y

    Теперь подставим это выражение во второе уравнение:

    (8y)+4y=10(8 - y) + 4y = 10

    8y+4y=108 - y + 4y = 10

    8+3y=108 + 3y = 10

    3y=1083y = 10 - 8

    3y=23y = 2

    y=23y = \frac{2}{3}

    Теперь найдем xx, используя первое уравнение:

    x=823=223x = 8 - \frac{2}{3} = \frac{22}{3}

    Ответ: x=223x = \frac{22}{3}, y=23y = \frac{2}{3}

  4. Система уравнений: x+2y=8-x + 2y = 8 x+4y=10x + 4y = 10

    Эта система имеет бесконечно много решений, так как второе уравнение можно получить, просто умножив первое уравнение на -1.

    Если вы хотите конкретное числовое решение, то добавьте дополнительное условие или ограничение.

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