Question

(√2 – √15)^2+(√5+√6)^2

Answer 1

Решение смотри на фотографии

Answer 2

V корень квадратный
1) ( V 2 - V 15 )^2 = 2 - 2V30 + 15 = 17 - 2V30
2) ( V5 + V6 )^2 = 5 + 2V30 + 6 = 11 + 2V30
3) 17 - 2V30 + 11 + 2V30 = 17 + 11 = 28
Ответ 28

Answer 3

To simplify the expression ($\sqrt{2} - \sqrt{15})^2 + (\sqrt{5} + \sqrt{6})^2$, you can expand it and then simplify.

Expanding the expression, you get:

$(\sqrt{2} - \sqrt{15})^2 = (\sqrt{2} - \sqrt{15})(\sqrt{2} - \sqrt{15})$

Using the FOIL (First, Outer, Inner, Last) method to expand this expression:

$\sqrt{2} \cdot \sqrt{2} + \sqrt{2} \cdot (-\sqrt{15}) + (-\sqrt{15}) \cdot \sqrt{2} + (-\sqrt{15}) \cdot (-\sqrt{15}) + (\sqrt{5} + \sqrt{6})^2$

Simplify each term:

\begin{align*} &2 - 2\sqrt{30} + 15 + 5 + 2\sqrt{30} + 6 \\ &= 22 \end{align*}

So, ($\sqrt{2} - \sqrt{15})^2 + (\sqrt{5} + \sqrt{6})^2$ simplifies to 22.