Question

3. 1) y = x², y = 0, x = 2; ​

Answer 1

Ответ:

y=x^2, x=2, y=0;

Находим пересечения, линий: (0,0) и (2,4)

Интересующая нас область расположена ниже параболы (y = x^2) и выше оси абсцисс (y=0). Справа ограничено прямой x=2.

Answer 2

It seems like you have an equation and some values, and you want to find a solution or interpret the given information. Let's break it down:

You have two equations:

1. y = x²
2. y = 0

And one value:

1. x = 2

To find the solution or understand what this means, let's analyze it step by step:

1. y = x²: This is a quadratic equation. It represents a parabola that opens upward. The vertex of this parabola is at the origin (0,0), and it goes through points like (1,1), (-1,1), (2,4), and (-2,4). It means that for any real number you plug in for 'x', you'll get a non-negative value for 'y'.

2. y = 0: This is a horizontal line at y = 0. In other words, it's the x-axis.

3. x = 2: This is a vertical line at x = 2.

Now, let's consider these three pieces of information together:

• The first equation, y = x², represents a parabola.
• The second equation, y = 0, represents the x-axis.

When you set these two equations equal to each other, you are essentially finding the points where the parabola intersects the x-axis, which is the line y = 0. These are the solutions to the equation.

Now, you want to find the x-values where these two equations are equal. So, you set y = x² equal to y = 0:

x² = 0

To solve this equation for x, you can take the square root of both sides:

x = 0

So, the solution to this system of equations is x = 0. When x is 0, both equations are satisfied.

The value x = 2 is not relevant in this context because it's not part of the system of equations. It's an additional piece of information you provided.