Question

(x-3)(2x+3)-(3-x)(x+1)

Answer 1

(х-3)(2х+3)+(х-3)(х+1)
(х-3)((2х+3)+(х+1))     вот преобразование

Упрощенный вариант
(х-3)(3х+4)
3х^2+4x-9x-12
3x^2-5x-12

Answer 2

(x-3)(2x+3)-(3-x)(x+1)=х*2х-3*2х+х*3-3*3  -  (3*х-х*х +3*1-х*1)= 2х в квадрате -6х+3х-9   -   (3х- х в квадрате +3-х)=3х в квадрате - 5х -12

Answer 3

To simplify the expression $(x-3)(2x+3) - (3-x)(x+1)$, let's use the distributive property:

First, we'll expand each set of parentheses:

For $(x-3)(2x+3)$, we have:

$(x-3)(2x+3) = x(2x) + x(3) - 3(2x) - 3(3)$ $= 2x^2 + 3x - 6x - 9$ $= 2x^2 - 3x - 9$

For $(3-x)(x+1)$, we have:

$(3-x)(x+1) = 3(x) + 3(1) - x(x) - x(1)$ $= 3x + 3 - x^2 - x$ $= -x^2 + 2x + 3$

Now, we'll substitute these simplified expressions back into the original equation:

$2x^2 - 3x - 9 - (-x^2 + 2x + 3)$

Next, we'll distribute the negative sign:

$2x^2 - 3x - 9 + x^2 - 2x - 3$

Combine like terms:

$3x^2 - 5x - 12$

So, $(x-3)(2x+3) - (3-x)(x+1) = 3x^2 - 5x - 12$.