Question

(1-с^2)-4c(1-c^2)+4c(1-C^2)

Answer 1

$(1 - {c}^{2} ) \times (1 - 4c + 4c) = (1 - c) \times (1 + c) \times 1 = 1(1 - c) \times (1 + c)$

Answer 2

Let's simplify the expression step by step:

(1 - c^2) - 4c(1 - c^2) + 4c(1 - C^2)

First, distribute the constants (4c) and (-4c) into the terms inside the parentheses:

1 - c^2 - 4c + 4c^3 + 4c - 4c^3

Now, notice that the terms -4c and 4c cancel each other out:

1 - c^2 + 4c^3 + 4c^3

Next, combine like terms:

1 - c^2 + 8c^3

So, the simplified expression is:

1 - c^2 + 8c^3