Question

(x+1)^3-x^2(x+3)+2=0

Answer 1

X^3+3x^2+3x+1-x^3-3x^2+2=0

3x+3=0

3x=-3

X=-1

Answer 2

(X+1)^3-x^2(x+3)+2=0;
X^3+3x+1-x^3+3x^3+2=0;
3x+3=0;
3x=0-3;
3x=-3;
X=-3:3;
X=-1
Ответ:-1

Answer 3

To solve the equation $(x+1)^3 - x^2(x+3) + 2 = 0$, you can follow these steps:

1. Expand the expressions: $(x+1)^3 = x^3 + 3x^2 + 3x + 1$ $x^2(x+3) = x^3 + 3x^2$

2. Substitute the expanded expressions back into the equation: $(x^3 + 3x^2 + 3x + 1) - (x^3 + 3x^2) + 2 = 0$

3. Simplify the equation: $x^3 + 3x^2 + 3x + 1 - x^3 - 3x^2 + 2 = 0$

4. Simplify further by canceling out like terms: $(3x + 1) + 2 = 0$

5. Combine the constants: $3x + 3 = 0$

6. Now, isolate $x$ by subtracting 3 from both sides: $3x = -3$

7. Finally, divide both sides by 3 to solve for $x$: $x = -1$

So, the solution to the equation $(x+1)^3 - x^2(x+3) + 2 = 0$ is $x = -1$.