Question

1) 3х² – 15 = 0 2) х² + 7х = 0

Answer 1

1)
3*(x2-5)=0
3*(x- под корнем 5)*(x+ под корнем 5)=0
ответ;под к. 5,- под к.5

Answer 2

Ответ:

3х²-15=0

3х²=15

х²=5

х=-√5

х=√5

х²+7х=0

х(х+7)=0

х=0. х+7=0

х=-7

Answer 3

To solve the given quadratic equations, let's find the values of $x$ that make each equation equal to zero.

1. $3x^2 - 15 = 0$: First, let's add 15 to both sides: $3x^2 = 15$

Now, divide both sides by 3 to isolate $x^2$: $x^2 = 5$

To solve for $x$, we'll take the square root of both sides, remembering to consider both the positive and negative square roots: $x = \pm \sqrt{5}$

So, the solutions for this equation are $x = \sqrt{5}$ and $x = -\sqrt{5}$.

2. $x^2 + 7x = 0$: First, factor out $x$ from the left-hand side: $x(x + 7) = 0$

Now, we have two potential factors that could make the equation equal to zero: $x = 0$ $x + 7 = 0$ $x = -7$

So, the solutions for this equation are $x = 0$ and $x = -7$.