Question

5x^2-12x+4=0////////////////////

Answer 1

Ответ:

0,4 и 2

Объяснение:

Находим дискриминант: D= b^2 - 4ac = 12^2 - 4*5*4 = 64 = 8^2

x1 = (-b - $\sqrt{D}$) / 2a = (12 - 8) / 10 = 0,4

x2 = (-b + $\sqrt{D}$) / 2a = (12 + 8) / 10 = 2

Answer 2

To solve the quadratic equation 5x^2 - 12x + 4 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 5, b = -12, and c = 4. Plug these values into the quadratic formula:

x = (-(-12) ± √((-12)² - 4(5)(4))) / (2(5))

Simplify:

x = (12 ± √(144 - 80)) / 10

x = (12 ± √64) / 10

Now, find the two possible solutions:

1. x = (12 + √64) / 10 = (12 + 8) / 10 = 20 / 10 = 2

2. x = (12 - √64) / 10 = (12 - 8) / 10 = 4 / 10 = 0.4

So, the solutions to the equation 5x^2 - 12x + 4 = 0 are x = 2 and x = 0.4.