Question

(-2/3)^2+2/3^3-3/(-3)^3

Answer 1

Ответ:

17/27

Объяснение:

(-2/3)^2+2/3^3-3/(-3)^3 = 17/27

Answer 2

To solve the expression $(-2/3)^2 + \frac{2}{3^3} - \frac{3}{(-3)^3}$, we'll break it down step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction):

1. First, let's square $-\frac{2}{3}$: $(-\frac{2}{3})^2 = \frac{4}{9}$

2. Next, let's calculate $\frac{2}{3^3}$: $\frac{2}{3^3} = \frac{2}{27}$

3. Lastly, let's calculate $\frac{3}{(-3)^3}$: $\frac{3}{(-3)^3} = \frac{3}{-27} = -\frac{1}{9}$

Now, let's substitute these values back into the original expression and simplify: $\frac{4}{9} + \frac{2}{27} - \left(-\frac{1}{9}\right)$

Now, we'll find a common denominator, which is 27: $\frac{12}{27} + \frac{2}{27} + \frac{1}{9}$

Combine the fractions: $\frac{12 + 2 + 3}{27} = \frac{17}{27}$

So, $(-2/3)^2 + \frac{2}{3^3} - \frac{3}{(-3)^3} = \frac{17}{27}$.