Question

5(x-2)-x=8-2(2-2x) 3(2x+1)=3(x+1)+2x

Answer 1

Ответ:

5(х-2)-х=8-2(2-2х)

5х-10-х=8-4-4х

4х+4х=8-4+10

8х=14

х=14:8

х=14/8

3(2х+1)=3(х+1)+2х

6х+3=3х+3+2х

6х-2х-3х=3-3

1х=0 - если результат =0, значит один из множников =0

Answer 2

Let's solve each equation step by step:

1. 5(x - 2) - x = 8 - 2(2 - 2x)

   Start by distributing the numbers outside the parentheses:

   5x - 10 - x = 8 - 4 + 4x

   Now, combine like terms on both sides of the equation:

   (5x - x) - 10 = (8 + 4x) - 4

   4x - 10 = 4x + 4

   Next, isolate the variable by moving all the x terms to one side and constants to the other:

   4x - 4x = 4 + 10

   0x = 14

   Since 0x is always equal to 0, there is no solution to this equation. The original equation is inconsistent.

2. 3(2x + 1) = 3(x + 1) + 2x

   Start by distributing the numbers outside the parentheses:

   6x + 3 = 3x + 3 + 2x

   Now, combine like terms on both sides of the equation:

   (6x - 3x - 2x) = 3 + 3

   6x - 5x = 6

   Simplify further:

   x = 6

   So, the solution to this equation is x = 6.