Question

Вероятность того, что стрелок при одном выстреле попадет в цель равна 0,8. Какова вероятность того, что стрелок первый раз промахнулся, а второй раз попадет в цель?

Answer 1

вероятность промаха равна 1=0.8=0.2

вероятность промаха первого выстрела и удачного попадания второго по правилу умножения равна 0.2*0.8=0.16

Answer 2

Calculating the Probability of Missing the First Shot and Hitting the Second Shot

The probability of the shooter missing the target with one shot is 0.8. We want to find the probability that the shooter misses the target on the first shot and hits it on the second shot.

To calculate this, we can use the complement rule, which states that the probability of an event occurring is 1 minus the probability of the event not occurring.

The probability of missing the target on the first shot is 0.8, and the probability of hitting the target on the second shot is 0.7.

Using the complement rule, the probability of missing the target on the first shot and hitting it on the second shot can be calculated as follows:

$$ P(\overline{A}) = q^1 = 0.2^1 = 0.2 $$ $$ P(A) = 1 - P(\overline{A}) = 1 - 0.2 = 0.8 $$

Therefore, the probability that the shooter misses the target on the first shot and hits it on the second shot is 0.8.

Additional Information

The probability of hitting the target with one shot is 0.8, and the probability of missing the target with one shot is 0.2 The probability of hitting the target on the second shot is 0.7, and the probability of missing the target on the second shot is 0.3 The combined probability of missing the target on the first shot and hitting it on the second shot is calculated as 0.8 * 0.7 = 0.56