Question

1*(-1)*2(-2)*......n*(-n)

Answer 1

Ответ:

сори не знаю:<:<

Объяснение:

подождите другого:<:<

Answer 2

The expression you provided, "1*(-1)2(-2)*...n(-n)," seems to represent a product of alternating positive and negative numbers. It looks like you want to calculate this product for a given positive integer value 'n'. Let's break it down:

1. The first number is 1.
2. The second number is -1.
3. The third number is 2.
4. The fourth number is -2.
5. This pattern continues until the nth number, which is (-1)^n * n.

To calculate the product of these numbers, you can use the following formula:

Product = 1 * (-1) * 2 * (-2) * ... * (-1)^n * n

This product will alternate between positive and negative values depending on whether 'n' is even or odd. If 'n' is even, the product will be positive; if 'n' is odd, the product will be negative.

If you want to compute the actual numerical value of this product for a specific 'n,' you can plug in the value of 'n' into the formula and calculate it. For example, if n = 4:

Product = 1 * (-1) * 2 * (-2) * (-1)^4 * 4 Product = 1 * (-1) * 2 * (-2) * 1 * 4 Product = -16

So, for n = 4, the product is -16.