Question

(2x+1,2)(x+1)(0,7x+0,21)=0​

Answer 1

произведение равно 0, когда один из множителей равен 0:

2х+1,2=0 или х+1=0 или 0,7х+0,21=0

2х=-1,2. _____х=-1_______0,7х=-0,21

х=-1,2:2=-0,6.__________х=(-0,21):0,7=-0,3

В ответе пишем 3 корня:

х1=-0,6

х2=-1

х3=-0,3

Answer 2

It looks like you've provided an equation in the form of a product of three factors set equal to zero:

(2x+1)(x+1)(0.7x+0.21) = 0

To find the solutions for x, you can use the zero-product property, which states that if a product of factors equals zero, then at least one of the factors must be equal to zero. So, you can set each factor equal to zero and solve for x separately:

1. 2x + 1 = 0 Subtract 1 from both sides: 2x = -1 Divide by 2: x = -1/2

2. x + 1 = 0 Subtract 1 from both sides: x = -1

3. 0.7x + 0.21 = 0 Subtract 0.21 from both sides: 0.7x = -0.21 Divide by 0.7: x = -0.21 / 0.7 x = -3/10

So, there are three solutions for x: x = -1/2, x = -1, and x = -3/10.