Question

2) 2 x(x+5)-(2x-8)(x +10)=0​

Answer 1

Ответ:

х = 40

Объяснение:

1) раскрываем скобки

2) 2x^2 + 10x - 2x^2 - 20x + 8x + 80 = 0 (знаки поменялись т.к. перед скобками стоял минус)

3) -2x + 80 = 0

4) -2x = -80

5) x = 40

Answer 2

To solve the equation 2x(x+5) - (2x-8)(x+10) = 0, you can follow these steps:

1. Expand the expressions: 2x(x+5) = 2x^2 + 10x (2x-8)(x+10) = 2x^2 + 20x - 8x - 80 = 2x^2 + 12x - 80

2. Rewrite the equation with the expanded expressions: 2x^2 + 10x - (2x^2 + 12x - 80) = 0

3. Distribute the negative sign on the right side of the equation: 2x^2 + 10x - 2x^2 - 12x + 80 = 0

4. Simplify the equation: (2x^2 - 2x^2) + (10x - 12x) + 80 = 0 0 - 2x + 80 = 0

5. Subtract 80 from both sides of the equation: -2x = -80

6. Divide both sides by -2 to solve for x: -2x / -2 = -80 / -2 x = 40

So, the solution to the equation 2x(x+5) - (2x-8)(x+10) = 0 is x = 40.