Question

{log}^{10} 5 + {log}^{10} 2​

Answer 1

Ответ:

= 1

Объяснение:

log_a x+log_a y=log_а (x×y)

x>0

y>0

$log_{10}5 + log_{10}2 = log_{10}(5 \times 2) = log_{10}10 = 1$

Answer 2

The expression $\log^{10} 5 + \log^{10} 2$ can be simplified using logarithm properties. In base 10 logarithms, we can use the property $\log_a (b) + \log_a (c) = \log_a (bc)$. Applying this property to the given expression:

$$\log^{10} 5 + \log^{10} 2 = \log^{10} (5 \times 2) = \log^{10} 10$$

Since $\log^{10} 10 = 1$ (any nonzero number raised to the power of 1 is itself), the expression simplifies to $1$. Therefore, $\log^{10} 5 + \log^{10} 2 = 1$.