Question

N1 Вычислите : 1. (15-√3)(15+√3) 2. (5-√2)^2+10√2 N2 Решите уравнение: 1. a^2-6a+5=0

Answer 1

Ответ:

№1.

$(15 - \sqrt{3 } )(15 + \sqrt{3} ) = 225 - 3 = 222$

${(5 - \sqrt{2} ) }^{2} + 10 \sqrt{2} = 25 - 10 \sqrt{2} + 2 + 10 \sqrt{2} = 25 + 2 = 27$

№2.

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Answer 2

N1:

1. (15 - √3)(15 + √3)

You can use the difference of squares formula, which states that (a - b)(a + b) = a^2 - b^2.

In this case, a = 15 and b = √3.

So, (15 - √3)(15 + √3) = 15^2 - (√3)^2 = 225 - 3 = 222.

N2:

1. a^2 - 6a + 5 = 0

To solve this quadratic equation, you can use the quadratic formula, which is given by:

a = (-b ± √(b^2 - 4ac)) / (2a)

In your equation, a = 1, b = -6, and c = 5.

a = (6 ± √((-6)^2 - 415)) / (2*1) a = (6 ± √(36 - 20)) / 2 a = (6 ± √16) / 2 a = (6 ± 4) / 2

Now, you have two possible solutions:

1. a = (6 + 4) / 2 = 10 / 2 = 5
2. a = (6 - 4) / 2 = 2 / 2 = 1

So, the solutions to the equation a^2 - 6a + 5 = 0 are a = 5 and a = 1.