Question

(2а-3)²+(3-2а)(3+2а)-3(а+2)(3а-1)

Answer 1

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Объяснение по этапное:

Answer 2

To simplify the given expression, let's expand and combine like terms:

(2a - 3)² + (3 - 2a)(3 + 2a) - 3(a + 2)(3a - 1)

First, expand the square of the binomial (2a - 3)²:

(2a - 3)(2a - 3) = 4a² - 12a + 9

Now, expand the product of the other two binomials (3 - 2a)(3 + 2a):

(3 - 2a)(3 + 2a) = 9 - 6a + 6a - 4a²

Notice that the middle terms cancel out, so you're left with 9 - 4a².

Now, expand the product of the last two binomials -3(a + 2)(3a - 1):

-3(a + 2)(3a - 1) = -3(3a² - a + 6a - 2)

Now, distribute the -3 to both terms inside the parentheses:

-3(3a² - a + 6a - 2) = -9a² + 3a - 18a + 6

Combine like terms:

-9a² - 15a - 6

Now, you can simplify the entire expression by combining these results:

(4a² - 12a + 9) + (9 - 4a²) - (-9a² - 15a - 6)

Now, combine like terms:

4a² - 12a + 9 + 9 - 4a² + 9a² + 15a + 6

Now, simplify further:

4a² - 4a² + 9a² - 12a + 15a + 9 + 9 + 6

Combine like terms again:

13a² + 3a + 24

So, the simplified expression is:

13a² + 3a + 24