Question

Sin(180°+a)-cos(90°+a) ​

Answer 1

$\displaystyle\bf\\Sin\Big(180^\circ+\alpha \Big)-Cos\Big(90^\circ+\alpha \Big)=-Sin\alpha -\Big(-Sin\alpha \Big)=\\\\=-Sin\alpha +Sin\alpha =0$

Answer 2

Ответ:

sin180*cos a-cos180*sin a+cos 90*cos a-sin90*sina=

=0*cos a-(-1)*sin a+0*cos a-1*sina=sina-sina=0

Объяснение:

Answer 3

To simplify the expression sin(180°+a) - cos(90°+a), you can use trigonometric identities.

1. sin(180°+a): Using the periodicity of the sine function, sin(180°+a) = -sin(a).

2. cos(90°+a): Using the periodicity of the cosine function, cos(90°+a) = sin(a).

Now, you can substitute these values back into the original expression:

-sin(a) - sin(a)

Now, you can combine like terms:

-2sin(a)

So, sin(180°+a) - cos(90°+a) simplifies to -2sin(a).