Question

4x^-1/ y^2 * y^-2/2x

Answer 1

$\displaystyle\bf\\\frac{4x^{-1} }{y^{2} } \cdot\frac{y^{-2} }{2x} =2\cdot x^{-1-1} \cdot y^{-2-2} =2x^{-2} y^{-4} =\frac{2}{x^{2} y^{4} }$

Answer 2

Ответ: 2/(y^4*x^2) у нас одинаковый ответ

Answer 3

To simplify the expression:

(4x^(-1) / y^2) * (y^(-2) / 2x)

You can follow these steps:

1. First, deal with the negative exponents by moving them to the opposite location in the fraction:

(4 / (x * y^2)) * (1 / (2x * y^2))

2. Now, you can multiply the numerators and the denominators separately:

Numerator: 4 * 1 = 4 Denominator: (x * y^2) * (2x * y^2) = 2x^2 * y^4

So, the simplified expression is:

4 / (2x^2 * y^4)

Now, you can simplify further if needed. For example, you can divide both the numerator and denominator by 2 to simplify the fraction:

(4 / 2) / (2x^2 * y^4 / 2)

2 / (x^2 * y^4)

That's the final simplified expression.