Question

X(X-3)-(x+2)(X+1)=10

Answer 1

X(x-3)-(x+2)(x+1)=10
x^2-3x-(x^2+x+2x+2)=10
x^2-3x-x^2-x-2x-2-10=0
-6x-12=0
-6x=12
-x=2
x=-2

Answer 2

Х(в квадрате)-3х-х(в квадрате)-х-2х-2=10
х(в квадрате) и -х(в квадрате) сокращается отсается
-3х-х-2х-2=10
-6х-2=10
-6х=12
х=-2

Answer 3

To solve the equation $X(X-3) - (X+2)(X+1) = 10$, you can follow these steps:

1. First, expand the expressions on both sides of the equation:

   $X(X-3) = X^2 - 3X$

   $(X+2)(X+1) = X^2 + 3X + 2$

   So the equation becomes:

   $X^2 - 3X - (X^2 + 3X + 2) = 10$

2. Next, simplify the equation:

   $X^2 - 3X - X^2 - 3X - 2 = 10$

3. Now, combine like terms on the left side of the equation:

   $-6X - 2 = 10$

4. Subtract 2 from both sides of the equation:

   $-6X = 10 + 2$

   $-6X = 12$

5. Finally, divide both sides by -6 to solve for X:

   $X = \frac{12}{-6}$

   $X = -2$

So, the solution to the equation $X(X-3) - (X+2)(X+1) = 10$ is $X = -2$.