Question

Sinx+siny\cosx+cosy=

Answer 1

=    Sin(x*y)\cos(x*y)

вроде бы  так !)

Answer 2

It seems like you want to simplify the expression $\sin(x) + \sin(y)\cos(x) + \cos(y)$. To do this, we can apply some trigonometric identities.

First, let's group the terms involving sine together:

$\sin(x) + \sin(y)\cos(x)$

Now, let's use the product-to-sum trigonometric identity $\sin(a)\cos(b) = \frac{1}{2}[\sin(a + b) + \sin(a - b)]$:

$\sin(x) + \frac{1}{2}[\sin(x + y) + \sin(x - y)] + \cos(y)$

Now, we can simplify the expression:

$\frac{1}{2}[\sin(x + y) + \sin(x - y)] + \sin(x) + \cos(y)$

So, the simplified expression is:

$\frac{1}{2}[\sin(x + y) + \sin(x - y)] + \sin(x) + \cos(y)$