Question

X^2+1/2x+1/18=0plizzzs

Answer 1

Х^2+1/2х+1/18=0
D=(1/2)^2-4×1×1/18=1/4-4/18=1/4-2/9=(9-8)/36=1/36
х1=(-1/2+1/6)/2=(-3+1)/6÷2=-2/6÷2= -1/6
з2=(-1/2-1/6)/2=(-3-1)/6÷2=-4/6÷2= -2/6= -1/3
ответ: х1= -1/6, х2= -1/3

Answer 2

It seems like you've provided a quadratic equation. To solve for the variable "x," we can use the quadratic formula:

For an equation of the form ax^2 + bx + c = 0, the quadratic formula is: x = (-b ± √(b² - 4ac)) / 2a

In your case, the equation is x^2 + (1/2)x + (1/18) = 0. Comparing with the general form ax^2 + bx + c = 0, we have: a = 1, b = 1/2, c = 1/18

Plugging these values into the quadratic formula: x = (-(1/2) ± √((1/2)² - 4 * 1 * (1/18))) / (2 * 1)

Simplify the expression under the square root: x = (-1/2 ± √(1/4 - 4/18)) / 2 x = (-1/2 ± √(9/36 - 8/36)) / 2 x = (-1/2 ± √(1/36)) / 2 x = (-1/2 ± 1/6) / 2

Now, calculate the two possible solutions for "x": x₁ = (-1/2 + 1/6) / 2 = 1/12 x₂ = (-1/2 - 1/6) / 2 = -2/3

So, the solutions for the equation x^2 + (1/2)x + (1/18) = 0 are x = 1/12 and x = -2/3.