Question

(9b^2-49)(1/3b-7-1/3 b+7)+b-13 при b=345

Answer 1

Фоточка тебе в помощь ;)

Answer 2

To find the value of the expression (9b^2 - 49)(1/3b - 7 - 1/3b + 7) + b - 13 when b = 345, follow these steps:

Step 1: Substitute the value of b into the expression.

(9(345)^2 - 49)(1/3(345) - 7 - 1/3(345) + 7) + 345 - 13

Step 2: Simplify the expression inside the parentheses.

(9(345)^2 - 49)(0) + 345 - 13

Step 3: Calculate the value inside the first parentheses.

(9 * 119025 - 49)(0) + 345 - 13

Step 4: Calculate the value inside the second parentheses.

(1071225 - 49)(0) + 345 - 13

Step 5: Perform the multiplication.

(1071176)(0) + 345 - 13

Step 6: Simplify further.

0 + 345 - 13

Step 7: Final calculation.

332

So, when b = 345, the expression evaluates to 332.