Question

(3х+2)^2-4х^2=0 7 класс алгебра срочно

Answer 1

(3x+2+2x)*(3x+2-2x)=0; (5x+2)*(x+2)=0; 5x+2=0 или x+2=0. 5x= -2, x1= -2/5. x2= -2. Ответ: x1= -2/5, x2= -2. 

Answer 2

To solve the equation $(3x+2)^2 - 4x^2 = 0$, follow these steps:

Step 1: Expand the equation: $(3x+2)^2 - 4x^2 = (3x + 2)(3x + 2) - 4x^2 = 9x^2 + 12x + 4 - 4x^2 = 5x^2 + 12x + 4$

Step 2: Set the equation equal to zero: $5x^2 + 12x + 4 = 0$

Step 3: Try to factor the quadratic equation or use the quadratic formula: The equation cannot be easily factored, so we'll use the quadratic formula to find the solutions for $x$: The quadratic formula is given by: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, for $ax^2 + bx + c = 0$, $a = 5$, $b = 12$, and $c = 4$.

Step 4: Plug the values into the quadratic formula and solve for $x$: $x = \frac{-12 \pm \sqrt{12^2 - 4 \cdot 5 \cdot 4}}{2 \cdot 5} = \frac{-12 \pm \sqrt{144 - 80}}{10} = \frac{-12 \pm \sqrt{64}}{10}$

Step 5: Simplify the square root: $x = \frac{-12 \pm 8}{10}$

Step 6: Find the two possible solutions for $x$: a) $x = \frac{-12 + 8}{10} = \frac{-4}{10} = -\frac{2}{5}$

b) $x = \frac{-12 - 8}{10} = \frac{-20}{10} = -2$

So, the two solutions to the equation are $x = -\frac{2}{5}$ and $x = -2$.