Question

A) 12y^3 _____ -42y^5 в) 5а^2. 5a _____ = ____ 6a. 6

Answer 1

$\frac{12y {}^{3} }{ - 42y {}^{5} } = \frac{4}{ - 15y {}^{2} } = - \frac{4}{15y {}^{2} } \\ \\ \frac{5a {}^{2} }{6a} = \frac{5a}{6}\: \: \: \: \: \: \: \frac{5a}{6} = \frac{5a}{6}$

Answer 2

A) To add 12y^3 and -42y^5, you need to combine the like terms. Since both terms have a common variable "y" raised to different powers, you cannot directly add them. The final answer would be:

12y^3 - 42y^5

B) To divide (5a^2 * 5a) by (6a * 6), you can simplify the expression by canceling out common factors:

(5a^2 * 5a) / (6a * 6)

First, combine the constants:

(25a^3) / (36a)

Next, you can simplify further by canceling out one "a" from the numerator and the denominator:

(25a^2) / 36

So the final answer is:

(25a^2) / 36