Question

Y²-9 дробь y³ умножить y дробь 3+y

Answer 1

$\frac{y^2-9}{y^3}* \frac{y}{3+y}= \frac{(y+3)(y-3)*y}{y^3(y+3)}= \frac{y-3}{y^2}$

Answer 2

$\frac{(y - 3)(y + 3)}{ {y}^{3} } \times \frac{y}{3 + y} = \frac{y - 3}{ {y}^{2} }$

Answer 3

To solve the expression, let's break it down step-by-step and simplify it:

1. y² - 9 can be factored as (y + 3)(y - 3).

2. y³ * y is equal to y^(3+1) = y⁴.

3. Now, we have y⁴ / ((y + 3)(3 + y)).

4. (y + 3) and (3 + y) are the same expressions, so we can rewrite the denominator as (y + 3)(y + 3) or (y + 3)².

5. Therefore, the expression becomes y⁴ / (y + 3)².

That's the simplified form of the expression: y⁴ / (y + 3)².