Question

3х(2х-5)=2(х²+2)срочно!!

Answer 1

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Answer 2

To solve the equation 3x(2x - 5) = 2(x² + 2), we need to find the value of x that makes the equation true. Let's go step by step:

Step 1: Distribute the terms on both sides of the equation.

3x(2x - 5) = 2(x² + 2) 6x² - 15x = 2x² + 4

Step 2: Move all the x terms to one side of the equation by subtracting 2x² from both sides.

6x² - 15x - 2x² = 2x² - 2x² + 4 4x² - 15x = 4

Step 3: Set the equation to zero by subtracting 4 from both sides.

4x² - 15x - 4 = 4 - 4 4x² - 15x - 4 = 0

Step 4: Solve the quadratic equation. You can use the quadratic formula or factorization. I'll use factorization here.

The equation can be factored as follows:

(4x + 1)(x - 4) = 0

Step 5: Set each factor to zero and solve for x.

4x + 1 = 0 or x - 4 = 0

For the first equation (4x + 1 = 0): 4x = -1 x = -1/4

For the second equation (x - 4 = 0): x = 4

So, the solutions to the equation are x = -1/4 and x = 4.