Question

8(5у+3)в квадрате+9(3у-1)в квадрате

Answer 1

8(5y+3)²+9(3y-1)²=8(25y²+30y+9)+9(9y²-6y+1)=
=200y²+240y+72+81y²-54y+9=281y²+186y+81

Answer 2

To simplify the given expression, we'll expand and combine like terms. The expression is:

$8(5у+3)^2 + 9(3у-1)^2$

Let's begin by expanding both squared terms:

$(5у + 3)^2 = (5у + 3) \cdot (5у + 3) = 25у^2 + 30у + 9$

$(3у - 1)^2 = (3у - 1) \cdot (3у - 1) = 9у^2 - 6у + 1$

Now, we substitute these expanded expressions back into the original expression:

$8(25у^2 + 30у + 9) + 9(9у^2 - 6у + 1)$

Next, distribute the coefficients:

$200у^2 + 240у + 72 + 81у^2 - 54у + 9$

Combine like terms:

$281у^2 + 186у + 81$

So the simplified expression is $281у^2 + 186у + 81$.