Question

Сократить дробь c^2-16/ (c-4)^2

Answer 1

$\frac{c^2-16}{(c-4)^2} = \frac{(c-4)(c+4)}{(c-4)^2} = \frac{c+4}{c-4}$

Answer 2

$\frac{c+4}{c(c-4)} = \frac{c+4)}{c^{2}-4c}$ $\frac{ c^{2}-16 }{(c-4)^{2} } = \frac{ c^{2}- 4^{2} }{(c-4)^{2} } = \frac{(c-4)(c+4)}{ c^{2}-8c+16 } = \frac{(c-4)(c+4)}{c(c-4)(c-4)}$

Answer 3

To simplify the given fraction (c^2 - 16) / (c - 4)^2, we can factor the numerator and the denominator and then cancel out common factors:

Step 1: Factor the numerator and denominator: c^2 - 16 can be factored as the difference of squares: (c + 4)(c - 4). (c - 4)^2 can be written as (c - 4)(c - 4).

Step 2: Cancel out common factors: Now, we can cancel out the common factor (c - 4) from the numerator and the denominator.

The simplified expression is: (c + 4) / (c - 4).