Question

3х²+7х-10=0 7х²+4х-11=0 6х²+5х-11=0

Answer 1

3х^2+7х-10=0
D=49+120=169
x1=-7+13/6=6/6=1
x2=-7-13/6= -20/6=-10/3

7x^2+4x-11=0
D=16+308=324
x1=-4+18/14= 14/14=1
x2= -4-18/14= -22/14=-11/7

6x^2+5x-11=0
D=25+264=289 
x1=-5+17/12=12/12=1
x2=-5-17/12=-22/12=-11/6

Answer 2

3х*3х+7-10=0
9х+7=0
9х=0-7
9х=-7
х=-7:9
х=-0,(7)
Ответ:х=-0,(7)

7х*7х+4х-11=0
49х+4х-11=0
53х=0+11
53х=11
х=11:53
х=020754717
Ответ:х=020754717


6х*6х+5х-11=0
36х+5х=0+11
41х=11
х=11:41
х=026829268
Ответ:х=026829268

Answer 3

To solve the quadratic equations, we can use the quadratic formula:

For a quadratic equation of the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / 2a

Let's use this formula to find the solutions for each of the given quadratic equations:

1. 3x² + 7x - 10 = 0 a = 3, b = 7, c = -10

x = (-7 ± √(7² - 4 * 3 * -10)) / 2 * 3 x = (-7 ± √(49 + 120)) / 6 x = (-7 ± √169) / 6 x = (-7 ± 13) / 6

So the solutions for this equation are: x = (6) / 6 = 1 x = (-20) / 6 = -10/3

2. 7x² + 4x - 11 = 0 a = 7, b = 4, c = -11

x = (-4 ± √(4² - 4 * 7 * -11)) / 2 * 7 x = (-4 ± √(16 + 308)) / 14 x = (-4 ± √324) / 14 x = (-4 ± 18) / 14

So the solutions for this equation are: x = (14) / 14 = 1 x = (-22) / 14 = -11/7

3. 6x² + 5x - 11 = 0 a = 6, b = 5, c = -11

x = (-5 ± √(5² - 4 * 6 * -11)) / 2 * 6 x = (-5 ± √(25 + 264)) / 12 x = (-5 ± √289) / 12 x = (-5 ± 17) / 12

So the solutions for this equation are: x = (12) / 12 = 1 x = (-22) / 12 = -11/6

To summarize:

1. 3x² + 7x - 10 = 0 has solutions x = 1 and x = -10/3
2. 7x² + 4x - 11 = 0 has solutions x = 1 and x = -11/7
3. 6x² + 5x - 11 = 0 has solutions x = 1 and x = -11/6