Question

Tg435° +tg375°=? Вычислить

Answer 1

$tg435 ^{o} +tg375 ^{o} =tg(180 ^{o} *3-15 ^{o)} +tg(360 ^{o}+15 ^{o} )=Ctg15 ^{o}+$ $+tg15 ^{o} = \frac{Cos15 ^{o} }{Sin15 ^{o} } + \frac{Sin15 ^{o} }{Cos15 ^{o} }= \frac{Cos ^{2}15 ^{o} +Sin ^{2}15 ^{o} }{Sin15 ^{o} Cos15 ^{o} } = \frac{1}{Sin15 ^{o}Cos15 ^{o} }= }$ $= \frac{1*2}{2Sin15 ^{o} Cos15 ^{o} } = \frac{2}{Sin30 ^{o} }= \frac{2}{ \frac{1}{2} }=4$

Answer 2

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Answer 3

To calculate the value of tg(435°) + tg(375°), we need to be mindful of the periodic nature of the tangent function. The tangent function has a period of 180 degrees, meaning that tan(x) = tan(x + 180°) for any angle x.

We can use this property to simplify the problem as follows:

tg(435°) = tg(435° - 360°) = tg(75°) tg(375°) = tg(375° - 360°) = tg(15°)

Now, we know the tangent values for 15° and 75°:

tg(15°) = 0.267949 tg(75°) = 3.732051

Finally, we can add the two tangent values together:

tg(435°) + tg(375°) = tg(75°) + tg(15°) = 3.732051 + 0.267949 = 4

So, tg(435°) + tg(375°) = 4.