Question

√2х-5 = √4х+7 срочно

Answer 1

$\sqrt{2x-5}= \sqrt{4x+7} \;\; \mid \; (^2) \\ \\ 2x-5=4x+7 \\ \\ -2x=12 \\ \\ x=-6$

При подстановке в корень у нас выйдет отрицательное значении под корнем. Значит  $x\in$ ∅ .

Answer 2

Возведём обе стороны в квадрат, получим:
2x-5=4x+7
2x-4x=7+5
-2x=12
X=-6

Answer 3

To solve the equation √(2x) - 5 = √(4x) + 7, follow these steps:

Step 1: Isolate one of the square root terms on one side of the equation.

√(2x) - √(4x) = 7 + 5

Step 2: Simplify the square roots.

√(2x) - √(2 * 2 * x) = 12

Step 3: Factor out the common factor from the second square root.

√(2x) - √(4 * x) = 12

Step 4: Simplify the square roots further.

√(2x) - 2√x = 12

Step 5: Move all terms with square roots to one side of the equation.

√(2x) - 2√x - 12 = 0

Step 6: Substitute u = √x to simplify the equation.

√(2u^2) - 2u - 12 = 0

Step 7: Solve the quadratic equation for u.

√2u^2 - 2u - 12 = 0

Step 8: Multiply the entire equation by √2 to get rid of the square root.

2u^2 - 2√2u - 12√2 = 0

Step 9: Solve the quadratic equation.

Using the quadratic formula: u = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 2, b = -2√2, and c = -12√2.

u = (2√2 ± √((-2√2)^2 - 4 * 2 * (-12√2))) / 2 * 2

u = (2√2 ± √(8 + 96√2)) / 4

u = (2√2 ± √(8(1 + 12√2))) / 4

u = (2√2 ± 2√(1 + 12√2)) / 4

u = (1 ± √(1 + 12√2))

Step 10: Substitute back u = √x.

√x = 1 ± √(1 + 12√2)

Step 11: Solve for x.

x = (1 ± √(1 + 12√2))^2

Please note that the solutions for x involve complex numbers and the expression inside the square root cannot be simplified further. Therefore, the final solution for x will be somewhat complicated with a real and imaginary part.

Without numerical values for √2 or √4, it is not possible to provide a specific numerical solution. If you have the numerical values for √2 and √4, you can substitute them into the equation to get the numerical solutions for x.