Question

(2a-1)в квадрате -(2a-3)(2a+3)=?

Answer 1

(2a-1)^2-(2a-3)(2a+3)=4a^2-4a+1-(4a^2-9)=4a^2-4a+1-4a^2+9=10-4a=2(5-2a)

Answer 2

To simplify the expression, let's first expand the squares and then apply the distributive property:

(2a - 1)² - (2a - 3)(2a + 3)

Expanding (2a - 1)²: (2a - 1)² = (2a - 1)(2a - 1) = 4a² - 2a - 2a + 1 = 4a² - 4a + 1

Expanding (2a - 3)(2a + 3): (2a - 3)(2a + 3) = 2a * 2a + 2a * 3 - 3 * 2a - 3 * 3 = 4a² + 6a - 6a - 9 = 4a² - 9

Now, let's put these results back into the original expression:

(2a - 1)² - (2a - 3)(2a + 3) = (4a² - 4a + 1) - (4a² - 9)

Now, distribute the negative sign in front of the second term:

(4a² - 4a + 1) - (4a² - 9) = 4a² - 4a + 1 - 4a² + 9

Now, combine like terms:

(4a² - 4a + 1 - 4a² + 9) = (4a² - 4a²) + (-4a + 1 + 9) = 0 - 4a + 10

Finally, the simplified expression is:

(2a - 1)² - (2a - 3)(2a + 3) = -4a + 10