Question

4а в квадрате -7 разложить на множители

Answer 1

[4a² - (√7)²] = (4a - √7)(4a + √7)

Answer 2

To factorize the expression 4а² - 7, we need to look for common factors or use other factorization methods. However, it seems there might be a typo in your expression. If you intended to write:

$4а^2 - 7$

Then we can proceed with the factorization:

Step 1: Recognize the difference of squares pattern. The given expression $4а^2 - 7$ is a difference of squares since it can be written as $(2а)^2 - (\sqrt{7})^2$.

Step 2: Apply the difference of squares formula. The difference of squares formula states that $a^2 - b^2 = (a + b)(a - b)$.

In this case, $a = 2а$ and $b = \sqrt{7}$, so we can factorize the expression as follows:

$4а^2 - 7 = (2а + \sqrt{7})(2а - \sqrt{7})$

So the expression $4а^2 - 7$ can be factored into $(2а + \sqrt{7})(2а - \sqrt{7})$.