Question

1)3(8x-6)=4(6x-4,5) 2)3(5x-7)=5(3x+0,2) 3)6(2x+1,6 дробью)=5(2,4x+0,2)

Answer 1

24х-18=24х-18
15х-21=15х+1
12х+9 3/5=12+1

Answer 2

To solve each equation, we need to find the value of 'x' that makes both sides of the equation equal. Let's go through each equation step-by-step:

1. $3(8x-6) = 4(6x-4.5)$

First, distribute the multiplication on both sides:

$24x - 18 = 24x - 18$

Now, notice that both sides are already equal. In this case, there are infinitely many solutions because no matter what value of 'x' we choose, both sides of the equation will remain equal.

2. $3(5x-7) = 5(3x+0.2)$

Again, distribute the multiplication:

$15x - 21 = 15x + 1$

Now, let's isolate 'x' on one side of the equation. We can do this by moving the term with 'x' to one side and the constant terms to the other side:

$15x - 15x = 1 + 21$

$0 = 22$

In this case, the equation leads to an inconsistency (0 ≠ 22). Therefore, there is no solution for this equation. The lines represented by both sides of the equation are parallel and will never intersect.

3. $6(2x+1.6) = 5(2.4x+0.2)$

Once again, distribute the multiplication:

$12x + 9.6 = 12x + 1$

Now, let's isolate 'x' by moving the constant terms to the other side:

$12x - 12x = 1 - 9.6$

$0 = -8.6$

As in the second equation, this equation also leads to an inconsistency (0 ≠ -8.6). Hence, there is no solution for this equation either. The lines represented by both sides are parallel and will never intersect.

In summary:

1. Infinitely many solutions.
2. No solution.
3. No solution.