Question

1) (8y-12)(2,1+0,3y)=0 2)7x-(4x+3)=3x+2

Answer 1

1) 8у-12=0

8у= -12

у = -1.5

2.1+0.3у=0

0.3у=2.1

у = 7

Ответ: -1.5;7

2) 7х-(4х+3)=3х+2

7х-4х-3=3х+2

7х-4х-3х=2

0х=2

Ответ: В уравнении нет корней

Answer 2

1) 8у-12=0

8у= -12

у = -1.5

2.1+0.3у=0

0.3у=2.1

у = 7

Ответ: -1.5;7

2) 7х-(4х+3)=3х+2

7х-4х-3=3х+2

7х-4х-3х=2

0х=2

Answer 3

Let's solve each equation step by step:

1. (8y - 12)(2.1 + 0.3y) = 0

To solve this equation, we need to find the values of 'y' that make the equation true. To do this, we can use the zero-product property, which states that if the product of two factors is zero, then at least one of the factors must be zero.

So, we set each factor equal to zero and solve for 'y':

1. 8y - 12 = 0 Add 12 to both sides: 8y = 12 Now, divide both sides by 8: y = 12 / 8 y = 1.5

2. 2.1 + 0.3y = 0 Subtract 2.1 from both sides: 0.3y = -2.1 Now, divide both sides by 0.3: y = -2.1 / 0.3 y = -7

Therefore, the solutions to the equation are y = 1.5 and y = -7.

2. 7x - (4x + 3) = 3x + 2

Let's simplify the equation first by removing the parentheses:

7x - 4x - 3 = 3x + 2

Now, combine like terms:

(7x - 4x) - 3 = 3x + 2 3x - 3 = 3x + 2

Next, we want to isolate 'x' on one side of the equation. Let's do that:

Subtract 3x from both sides:

3x - 3 - 3x = 3x + 2 - 3x -3 = 2

Now, we can see that we have a false statement (-3 = 2), which means there is no value of 'x' that makes the equation true. Therefore, the original equation has no solution. This means there are no solutions for 'x' in this equation.