Question

(y-2(y+1)=0 2х-(8-х)+(3х-2)=6х-10

Answer 1

(y-2(y+1))=0

y-2y-2=0

-y-2=0

-y=2

y= -2

2x-(8-x)+(3x-2)=6x-10

2x-8+x+3x-2=6x-10

6x-10=6x-10

Бесконечное множество ответов

Answer 2

Let's solve the two equations step by step:

1. y - 2(y + 1) = 0

To solve this equation, first distribute the -2 on the left side:

y - 2y - 2 = 0

Now combine the y terms:

-y - 2 = 0

To isolate y, add 2 to both sides:

-y = 2

Finally, multiply both sides by -1 to get the value of y:

y = -2

2. 2x - (8 - x) + (3x - 2) = 6x - 10

First, simplify the equation by removing the parentheses:

2x - 8 + x + 3x - 2 = 6x - 10

Now, combine the x terms on both sides:

6x - 10 = 6x - 10

In this case, notice that the variables on both sides are the same, and the equation is true for any value of x. Therefore, this equation has infinitely many solutions and is considered an "identity."

So, the solutions to the given equations are:

1. y = -2
2. The equation 2x - (8 - x) + (3x - 2) = 6x - 10 is an identity and holds true for any value of x.