Question

B-a/2:a^2=b^2/4 при a=-3/4 и b=7/4

Answer 1

3/4-7/4÷3/4^2/4 вот так ч понила у меня тоже есть почти такие задание

Answer 2

1) B-(a/2)/a^2 =b^2/4, при a=-3/4  и b=7/4

2) b-(a/2)/a^2 =b^2/4, при a=-3/4  и b=7/4

Answer 3

To check whether the given equation is true for the values of a and b provided, we can simply substitute the values and see if both sides of the equation are equal.

Given equation: (B - a/2) : a^2 = b^2/4

Let's substitute a = -3/4 and b = 7/4:

Left-hand side (LHS) = (B - (-3/4) / 2) / (-3/4)^2 = (B + 3/8) / (9/16) = (16/9) * (B + 3/8) = (16B + 3) / 9

Right-hand side (RHS) = (7/4)^2 / 4 = (49/16) / 4 = 49/64

Now, we have:

LHS = (16B + 3) / 9 RHS = 49/64

Since the equation doesn't state any relationship between B and a, we can treat B as a constant for this evaluation.

Now, let's check if the equation holds true for a = -3/4 and b = 7/4:

(16B + 3) / 9 = 49/64

To find the value of B, we can cross-multiply:

64 * (16B + 3) = 9 * 49

Expand the equation:

1024B + 192 = 441

Now, isolate B:

1024B = 441 - 192 1024B = 249 B = 249 / 1024

Therefore, the value of B is 249/1024, and the given equation is true for a = -3/4 and b = 7/4 with B = 249/1024.