Question

Дана линейная функция y =2/3+6х Найдите хочу, если у=1, у=-1, у=-2/3, у=5

Answer 1

1. Y=1:

1 = 2/3 + 6x

6x = 1-2/3

6x=1/3

x = 1/3*1/6 = 1/18

2. Y=-1

-1=2/3+6x

6x=-1-2/3

6x=-5/3

x=-5/3*1/6=-5/18

3, Y = -2/3

-2/3 = 2/3+6x

6x = -2/3-2/3

6x=-4/3

x = -4/3*1/6 = -4/18 = -2/9

4. Y = 5

5 = 2/3 + 6x

6x = 5-2/3

6x = 13/3

x = 13/3 * 1/6 = 13/18

Answer 2

To find the value of x for each given value of y in the linear function y = (2/3) + 6x, we can simply substitute the given values of y into the equation and solve for x. Let's do that step by step:

1. When y = 1: 1 = (2/3) + 6x

To isolate x, subtract (2/3) from both sides: 6x = 1 - (2/3) 6x = (3/3) - (2/3) 6x = 1/3

Now, divide both sides by 6: x = (1/3) / 6 x = 1/3 * 1/6 x = 1/18

So, when y = 1, x = 1/18.

2. When y = -1: -1 = (2/3) + 6x

To isolate x, subtract (2/3) from both sides: 6x = -1 - (2/3) 6x = -(3/3) - (2/3) 6x = -5/3

Now, divide both sides by 6: x = (-5/3) / 6 x = (-5/3) * (1/6) x = -5/18

So, when y = -1, x = -5/18.

3. When y = -2/3: -2/3 = (2/3) + 6x

To isolate x, subtract (2/3) from both sides: 6x = -2/3 - 2/3 6x = -4/3

Now, divide both sides by 6: x = (-4/3) / 6 x = (-4/3) * (1/6) x = -4/18 x = -2/9

So, when y = -2/3, x = -2/9.

4. When y = 5: 5 = (2/3) + 6x

To isolate x, subtract (2/3) from both sides: 6x = 5 - 2/3

To make the calculation easier, let's express 5 as a fraction with a common denominator of 3: 5 = 15/3

Now, the equation becomes: 6x = 15/3 - 2/3 6x = 13/3

Now, divide both sides by 6: x = (13/3) / 6 x = (13/3) * (1/6) x = 13/18

So, when y = 5, x = 13/18.

To summarize:

• When y = 1, x = 1/18
• When y = -1, x = -5/18
• When y = -2/3, x = -2/9
• When y = 5, x = 13/18