Question

Tg фи=1, фи принадлежит (p/2, 3p/2) ????

Answer 1

$tg\varphi =1\; \; \to \; \; \varphi =\frac{\pi}{4}+\pi n\; ,\; n\in Z\\\\\varphi \in \Big (\frac{\pi }{2}, \frac{3\pi }{2}\, \Big )\; \; \to \; \; \varphi =\frac{\pi }{4}+\pi =\frac{5\pi }{4}$

Answer 2

It seems like you're asking about trigonometric functions, specifically the value of the tangent function (Tg) of an angle (φ) that belongs to the interval (π/2, 3π/2).

In trigonometry, the tangent function (Tg or tan) is defined as the ratio of the sine (sin) to the cosine (cos) of an angle:

Tg(φ) = sin(φ) / cos(φ)

However, we need more information to provide a specific numerical value for Tg(φ). In this case, you need to know the value of φ, which lies within the interval (π/2, 3π/2) to calculate Tg(φ).

For example, if you are given the value of φ, say φ = π, then you can calculate Tg(π) as follows:

Tg(π) = sin(π) / cos(π)

The exact value of sin(π) is 0, and cos(π) is -1. Therefore, Tg(π) = 0 / (-1) = 0.

But since you haven't provided the specific value of φ, I can't give you the exact numerical value of Tg(φ). Please provide the value of φ within the given interval, and I'll be happy to help you calculate Tg(φ).