Question

Cos(π-a)+ctg(π+a)+tg(π\2+a)-sin(3π\2+a)

Answer 1

ctg(π/2 - a) меняется на tga, а sin(3π/2 - a) на cosa, то получается tga-tga+cos/cos= 0+1=1

Answer 2

Надеюсь поймёшь;) удачи

Answer 3

Let's simplify the expression step by step:

1. Cos(π - a) = -cos(a) [cosine is an even function]

2. Ctg(π + a) = cot(π + a) = cot(a) [cotangent is a periodic function with period π]

3. Tg(π/2 + a) = tan(π/2 + a) = -cot(a) [tangent is the reciprocal of cotangent]

4. Sin(3π/2 + a) = -sin(a) [sine is an odd function]

Now, the original expression can be written as:

-cos(a) + cot(a) - cot(a) - sin(a)

Next, combine the terms with cot(a):

-cos(a) - 2cot(a) - sin(a)

This is the simplified expression for Cos(π - a) + Ctg(π + a) + Tg(π/2 + a) - Sin(3π/2 + a).