Question

√48-√12-√108+√75+√27=

Answer 1

$4 \sqrt{3} - 2 \sqrt{3} - 6 \sqrt{3} + 5 \sqrt{3} + 3 \sqrt{3} = 4 \sqrt{3}$

Answer 2

Выносим √3 за скобки и выделяем корни: √3(4-2-6+5+3)=4√3

Answer 3

To simplify the expression √48 - √12 - √108 + √75 + √27, first, we need to find the square roots of the numbers:

√48 = √(16 * 3) = √16 * √3 = 4√3 √12 = √(4 * 3) = √4 * √3 = 2√3 √108 = √(36 * 3) = √36 * √3 = 6√3 √75 = √(25 * 3) = √25 * √3 = 5√3 √27 = √(9 * 3) = √9 * √3 = 3√3

Now, substitute these values into the original expression:

4√3 - 2√3 - 6√3 + 5√3 + 3√3

Now, combine the like terms:

(4 - 2 - 6 + 5 + 3)√3 = 4√3

So, the simplified expression is 4√3.