Question

Решить уравнение 3x^2-8x+9=0

Answer 1

Решение смотрите в приложении.

Answer 2

To solve the quadratic equation 3x^2 - 8x + 9 = 0, we can use the quadratic formula, which is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

For the given equation, a = 3, b = -8, and c = 9. Now, let's plug these values into the quadratic formula and solve for x:

x = (-( -8) ± √((-8)^2 - 4 * 3 * 9)) / (2 * 3) x = (8 ± √(64 - 108)) / 6 x = (8 ± √(-44)) / 6

Since we have a negative value under the square root (√(-44)), the solutions will involve complex numbers. We can express the square root of -44 as √(-1 * 44), which is √(-1) * √(44), or simply "i" * √(44) in terms of the imaginary unit "i".

x = (8 ± i√44) / 6 x = (8 ± 2i√11) / 6

Now, we have two solutions for x:

1. x = (8 + 2i√11) / 6
2. x = (8 - 2i√11) / 6

These are the two complex solutions to the given quadratic equation.