Question

2х^2+48x+64 при х= -8

Answer 1

подставь вместо х   -8.

2*(-8)²+48*(-8)+64=2*64-48*8+64=128-384+64=-192

Answer 2

2х^2+48x+64 = 2х²+48x+64 = 2(х²+24х+128 - 128 + 32) = 2( (х+16)(х+8) - 96) = 2(8*0 - 96) = -192

Answer 3

To evaluate the expression 2x^2 + 48x + 64 when x = -8, we simply substitute -8 in place of x and calculate the result.

2(-8)^2 + 48(-8) + 64

Now, we follow the order of operations: first, calculate -8 squared, then perform the multiplication, and finally the addition and subtraction.

(-8)^2 = 64

2 * 64 = 128

48 * (-8) = -384

Now, add the previous results:

128 - 384 + 64 = -192 + 64 = -128

So, when x = -8, the value of the expression 2x^2 + 48x + 64 is -128.