Question

А)x^2+2x-y^2+2y при х=0.7; у=0.3б)а^2-2b-a-4b^2 при а=1,6;b=0.8в)х^3+х^2у-ху^2-у^3 при х=7.37; у=2.63

Answer 1

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Answer 2

To evaluate the given expressions, simply substitute the provided values for the variables. Let's calculate the results for each case:

а) x^2 + 2x - y^2 + 2y when x=0.7 and y=0.3:

Substitute x=0.7 and y=0.3 into the expression: (0.7)^2 + 2(0.7) - (0.3)^2 + 2(0.3)

Calculate the result: 0.49 + 1.4 - 0.09 + 0.6 = 2.4

So, the result is 2.4.

б) a^2 - 2b - a - 4b^2 when a=1.6 and b=0.8:

Substitute a=1.6 and b=0.8 into the expression: (1.6)^2 - 2(0.8) - 1.6 - 4(0.8)^2

Calculate the result: 2.56 - 1.6 - 1.6 - 4(0.64) = 2.56 - 1.6 - 1.6 - 2.56 = -2.2

So, the result is -2.2.

в) x^3 + x^2y - x*y^2 - y^3 when x=7.37 and y=2.63:

Substitute x=7.37 and y=2.63 into the expression: (7.37)^3 + (7.37)^2(2.63) - 7.37(2.63)^2 - (2.63)^3

Calculate the result: 395.898913 + 170.117001 + 18.938841 - 18.938841 = 565.115914

So, the result is 565.115914.