Question

(6m-1)(6m+1)-5m(4m-1)=(4m+3)(4m-3) m=?

Answer 1

(6m - 1)(6m + 1) - 5m(4m - 1) = (4m + 3)(4m - 3)

36m² - 1 - 20m² + 5m = 16m² - 9

16m² + 5m - 1 - 16m² + 9 = 0

5m + 8 = 0

5m = - 8

m = - 1,6

Answer 2

таким образом ответ m=1.6 ,если на картинке чо то не понятно то то напишите в коментах

Answer 3

Let's solve the equation step by step:

1. Expand the expressions on both sides of the equation:

Left-hand side (LHS): (6m - 1)(6m + 1) - 5m(4m - 1)

Expanding the first part using the distributive property: = 36m^2 + 6m - 6m - 1

Simplifying: = 36m^2 - 1

Expanding the second part: = 5m * 4m - 5m * (-1) = 20m^2 + 5m

So the LHS becomes: = 36m^2 - 1 + 20m^2 + 5m = 56m^2 + 5m - 1

Right-hand side (RHS): (4m + 3)(4m - 3)

Expanding using the distributive property: = 16m^2 - 12m + 12m - 9

Simplifying: = 16m^2 - 9

2. Now we have the equation:

LHS = RHS

So, we equate the two expressions we found:

56m^2 + 5m - 1 = 16m^2 - 9

3. Move all the terms to one side to solve for 'm':

56m^2 + 5m - 1 - 16m^2 + 9 = 0

Combine like terms:

(56m^2 - 16m^2) + 5m + 9 - 1 = 0

40m^2 + 5m + 8 = 0

4. Now, we can attempt to solve the quadratic equation. However, it appears that this quadratic equation has no real roots. To confirm this, we can calculate the discriminant (D) of the quadratic equation (ax^2 + bx + c = 0):

Discriminant (D) = b^2 - 4ac

In our case, a = 40, b = 5, and c = 8:

D = 5^2 - 4 * 40 * 8 D = 25 - 160 D = -135

Since the discriminant is negative, the quadratic equation has no real roots. Therefore, there is no real value of 'm' that satisfies the equation:

(6m - 1)(6m + 1) - 5m(4m - 1) = (4m + 3)(4m - 3)